(x+2)(x+)=x^2-10

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Solution for (x+2)(x+)=x^2-10 equation:



(x+2)(x+)=x^2-10
We move all terms to the left:
(x+2)(x+)-(x^2-10)=0
We add all the numbers together, and all the variables
(x+2)(+x)-(x^2-10)=0
We get rid of parentheses
-x^2+(x+2)(+x)+10=0
We multiply parentheses ..
-x^2+(+x^2+2x)+10=0
We add all the numbers together, and all the variables
-1x^2+(+x^2+2x)+10=0
We get rid of parentheses
-1x^2+x^2+2x+10=0
We add all the numbers together, and all the variables
2x+10=0
We move all terms containing x to the left, all other terms to the right
2x=-10
x=-10/2
x=-5

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